X^2-2x+.92=0

Solution for X^2-2x+.92=0 equation:

X^2-2X+.92=0

We add all the numbers together, and all the variables

X^2-2X+0.92=0

a = 1; b = -2; c = +0.92;
Δ = b2-4ac
Δ = -22-4·1·0.92
Δ = 0.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{0.32}}{2*1}=\frac{2-\sqrt{0.32}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{0.32}}{2*1}=\frac{2+\sqrt{0.32}}{2}
$